In the Linux kernel, the following vulnerability has been resolved: mm/slab_common: fix possible double free of kmem_cache When doing slub_debug test, kfence's 'test_memcache_typesafe_by_rcu' kunit test case cause a use-after-free error: BUG: KASAN: use-after-free in kobject_del+0x14/0x30 Read of size 8 at addr ffff888007679090 by task kunit_try_catch/261 CPU: 1 PID: 261 Comm: kunit_try_catch Tainted: G B N 6.0.0-rc5-next-20220916 #17 Hardware name: QEMU Standard PC (i440FX + PIIX, 1996), BIOS 1.15.0-1 04/01/2014 Call Trace: <TASK> dump_stack_lvl+0x34/0x48 print_address_description.constprop.0+0x87/0x2a5 print_report+0x103/0x1ed kasan_report+0xb7/0x140 kobject_del+0x14/0x30 kmem_cache_destroy+0x130/0x170 test_exit+0x1a/0x30 kunit_try_run_case+0xad/0xc0 kunit_generic_run_threadfn_adapter+0x26/0x50 kthread+0x17b/0x1b0 </TASK> The cause is inside kmem_cache_destroy(): kmem_cache_destroy acquire lock/mutex shutdown_cache schedule_work(kmem_cache_release) (if RCU flag set) release lock/mutex kmem_cache_release (if RCU flag not set) In some certain timing, the scheduled work could be run before the next RCU flag checking, which can then get a wrong value and lead to double kmem_cache_release(). Fix it by caching the RCU flag inside protected area, just like 'refcnt'
Published 2024-04-28 13:15:07
Updated 2025-01-10 17:49:54
Source Linux
View at NVD,   CVE.org
Vulnerability category: Memory Corruption

Products affected by CVE-2022-48649

Exploit prediction scoring system (EPSS) score for CVE-2022-48649

0.07%
Probability of exploitation activity in the next 30 days EPSS Score History
~ 17 %
Percentile, the proportion of vulnerabilities that are scored at or less

CVSS scores for CVE-2022-48649

Base Score Base Severity CVSS Vector Exploitability Score Impact Score Score Source First Seen
7.8
HIGH CVSS:3.1/AV:L/AC:L/PR:L/UI:N/S:U/C:H/I:H/A:H
1.8
5.9
NIST 2025-01-10

CWE ids for CVE-2022-48649

  • The product calls free() twice on the same memory address.
    Assigned by: nvd@nist.gov (Primary)
  • The product reuses or references memory after it has been freed. At some point afterward, the memory may be allocated again and saved in another pointer, while the original pointer references a location somewhere within the new allocation. Any operations using the original pointer are no longer valid because the memory "belongs" to the code that operates on the new pointer.
    Assigned by: nvd@nist.gov (Primary)

References for CVE-2022-48649

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